Physics, asked by ashley88, 1 year ago

two stones having masses in the ratio 3 is to 2 at dropped from the Heights in the ratio 4 is to 9 the ratio of magnitudes of the linear momentum just before reaching the ground is( neglect air resistance)

Answers

Answered by ZiaAzhar89
0
Heya

As velocity just after drop is root2gh for every object

Therefore


Ratio of masses = M/m = 3:2
Ratio of height= H/h = 4:9
u = 0m/s v = ?
g=10m/s
For finding the velocity of the stones with H;

velocity with h height;

Ratio of linear momentum of the 2 stones;
P/p = MV/mv=1:1
Therefore, the ratio of the linear momentum of the two stones is 1:1

Attachments:

nikhil497146: miss,I think the heights are not same so the velocities will be different and also the momentum then how did you got 1:1. PLEASE REPLY TO ME MISS
Answered by nikhil497146
0
GLAD YOU LIKE IT
FROM WHICH BOOK DID YOU PICKED THAT QUESTION???
Attachments:
Similar questions