two stones having masses in the ratio 3 is to 2 at dropped from the Heights in the ratio 4 is to 9 the ratio of magnitudes of the linear momentum just before reaching the ground is( neglect air resistance)
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Heya
As velocity just after drop is root2gh for every object
Therefore
Ratio of masses = M/m = 3:2
Ratio of height= H/h = 4:9
u = 0m/s v = ?
g=10m/s
For finding the velocity of the stones with H;
velocity with h height;
Ratio of linear momentum of the 2 stones;
P/p = MV/mv=1:1
Therefore, the ratio of the linear momentum of the two stones is 1:1
As velocity just after drop is root2gh for every object
Therefore
Ratio of masses = M/m = 3:2
Ratio of height= H/h = 4:9
u = 0m/s v = ?
g=10m/s
For finding the velocity of the stones with H;
velocity with h height;
Ratio of linear momentum of the 2 stones;
P/p = MV/mv=1:1
Therefore, the ratio of the linear momentum of the two stones is 1:1
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nikhil497146:
miss,I think the heights are not same so the velocities will be different and also the momentum then how did you got 1:1. PLEASE REPLY TO ME MISS
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