Question

Two stones, having masses in the ratio of 3 : 2, are

dropped from the heights in the ratio of 4 : 9. The

ratio of magnitudes of their linear momenta just

before reaching the ground is (neglect air resistance)

(1) 4 : 9 (2) 2 : 3

(3) 3 : 2 (4) 1 : 1

Answer 1

v²=u²+2as here in both case u will be zero

momentum(p)=velocity × mass

here we need v

v=√2as   (a=g=10m/s²)

in first case v = √2×10×4 =4√5

p = 4√5 × 3

= 12√5

in case 2

v=√2×10×9

= 6√5

p= 6√5 × 2

=12√5

HENCE RATIO IS 1:1

MAKE BRAINLIEST

Answer 2

I hope it will be helpful