two stones having masses in the ratio of 3:2 are dropped from the height in the ratio of 4:9the ratio of magnitudes of the linear momenta just before reaching the ground is (neglect air resistance)
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Let the ratio be=3x:2x
Ratio of magnitude of momenta is =mv of first stone:mv of second stone
Ratio=3x*4:2x*9
=12x:18x
=2:3
Is your answer
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