Two stones having masses in the ratio of 3:2 are dropped from a height in the ratio 4:9 .What will be the magnitude of their linear momentum just before reaching the ground
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mgh=1/2mv^2
=>v=√(2gh)
Then the ratio is=3×√4:2×√9
=6:6=1:1
=>v=√(2gh)
Then the ratio is=3×√4:2×√9
=6:6=1:1
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