Two stones having masses in the ratio of 3:2, are dropped from the heights in the ratio of 4:9. The ratio of magnitudes of their linear momenta just before reaching the ground is(neglect air resistence)
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linear momentum .= mass X velocity
in v²-u²= 2 as , u =0 in both cases ,
v²= 2 as
solve v in both cases. then put in linear momentum equation
u will get same ratio 1:1
in v²-u²= 2 as , u =0 in both cases ,
v²= 2 as
solve v in both cases. then put in linear momentum equation
u will get same ratio 1:1
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