Question

Two stones having masses in the ratio of 3:4 are dropped from a height in the ratio 4:9 .What will be the magnitude of their linear momentum just before reaching the ground

Answer 1

1:2 is the answer of ur question. Hope it will help you.

Answer 2

Given :

Two stones with masses in the ratio =m1:m2 =3:4

Height ratio :h:H=4:9

As it is free fall, u= 0 m/s

v=?

g=10m/s²

From the third equation of motions :

V²-u²=2gh

for first case :

V²-0²=2x10x4

v²=80m/s

v=2√20 m/s

Second case :

V²-0²=2x10x9

v²=180m/s

v=3√20 m/s

Now linear momentum= mass x velocity

So ratios of linear momentum : p1:p2= 3x2√20:4x3√20

=2:4

=1:2

P1:P2=1:2