Question

Two stones of masses in the ratio 3:2, are dropped from the heights in the ratio 4:9. The ratio of magnitudes of their linear momenta just before reaching the ground is

Answer 1

Ratio will be 1:1.

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Answer 2

Ratio of masses = M/m = 3:2

Ratio of height= H/h = 4:9

u = 0m/s v = ?

g=10m/s

For finding the velocity of the stones with H;

velocity with h height;

Ratio of linear momentum of the 2 stones;

P/p = MV/mv=1:1

Therefore, the ratio of the linear momentum of the two stones is 1:1