Question

Two stones of masses m1 and m2 are let fall from heights 2h and h, their moment on reaching the ground are in the ratio ​

Answer 1

Explanation:

first of all we all know that time does not depend on the mass of free falling object

so the m1 and m2 are not considerable

now according to second rule of motion

for free falling object

distance is S

initial velocity is u which is 0

time is t

and acceleration is gravity

which is g

now

$s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 + \frac{1}{2} g {t}^{2} \\ since \: g \: is \: constant \\ t = \sqrt{s}$

since time depend directly on the distance , so now

ration of moment of m¹ and m² will be

$\frac{m1}{m2} = \frac{ \sqrt{2h} }{ \sqrt{h} } \\ \frac{m1}{m2} = \frac{ \sqrt{2} }{1}$