Two stones thrown at different angles have same initial velocity and same range. If H is the maximum height attained by one stone thrown at an angle of 30°, then the maximum height attained by the other stone is (b) H (c) 2H (d) 3H
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Explanation :- case 1 :-when body moves upward direction.
initial velocity =u
final velocity =v=0
now, v=u+at
Here, v=0,a=−g [acceleration is downward direction]
0=u−gt⇒t=u/g
Maximum height = h
u
2
=2gh⇒h=u
2
/2g---(1)
Answered by
0
Explanation:
Assuming the angle of projection is = π/3 radians:
2
π
−
3
π
=
6
π
radians
⇒ the angle of projection of the other object
let the maximum heights be: h
1
and h
2
:
h
2
h
1
=
sin
2
(
6
π
)
sin
2
(
3
π
)
h
2
h
1
=
(
2
1
)
2
(
2
3
)
2
h
2
h
1
=
(
4
1
)
(
4
3
)
=
1
3
h
2
=
3
h
1
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