Math, asked by arahmanzaffar, 2 days ago

Two straight line intersect such that the sum of a pair vertically opposite angles formed is 280 find by the value of all the four angles

Answers

Answered by khakharoshan4
1

Answer:

From the figure we know that ∠AOD and ∠BOC are vertically opposite angles ∠AOD=∠BOC

It is given that

∠BOC+∠AOC=280

o

we know that ∠AOD=∠BOC

so it can be written as

∠AOD+∠AOD=180

o

2∠AOD=280

o

∠AOD=

2

180

∠AOD=∠BOC=140

o

From the figure we know that ∠AOC and ∠AOC form a linear pair

So it can be written as

∠AOC+∠AOD=180

o

substituting the values

∠AOC+140

o

=180

o

∠AOC=40

o

From the figure we know that ∠AOC and ∠BOD are vertically opposite angles

∠AOC=∠BOD=40

o

Therefore ∠AOC=40

o

, ∠BOC=140

o

, ∠AOD=140

o

, ∠BOD=40

o

Answered by Anonymous
1

Answer:

Answer:

From the figure we know that ∠AOD and ∠BOC are vertically opposite angles ∠AOD=∠BOC

It is given that

∠BOC+∠AOC=280

o

we know that ∠AOD=∠BOC

so it can be written as

∠AOD+∠AOD=180

o

2∠AOD=280

o

∠AOD=

2

180

∠AOD=∠BOC=140

o

From the figure we know that ∠AOC and ∠AOC form a linear pair

So it can be written as

∠AOC+∠AOD=180

o

substituting the values

∠AOC+140

o

=180

o

∠AOC=40

o

From the figure we know that ∠AOC and ∠BOD are vertically opposite angles

∠AOC=∠BOD=40

o

Therefore ∠AOC=40

o

, ∠BOC=140

o

, ∠AOD=140

o

, ∠BOD=40

o

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