Question

Two straight lines AB and CD intersect at 0 . If angle ∠COT =60, Find a,b,c

Answer 1

Step-by-step explanation:

Since AB and CD intersect at O

Since AB and CD intersect at O⇒ ∠BOD = ∠AOC ⇒ a = 4b …. (i)Also a + b + 60° = 180° Þ a + b = 120° …. (ii) or 4b + b = 120° ⇒ 5b = 120° ⇒ b = 24° ⇒ a = 4b = 4 x 24 = 96°Since ∠AOD = ∠COB …. (Vertically opposite angles) ⇒ 2c = 60° + b ⇒ 2c = 60° + 24° = 84° ... c = 42°

Since AB and CD intersect at O⇒ ∠BOD = ∠AOC ⇒ a = 4b …. (i)Also a + b + 60° = 180° Þ a + b = 120° …. (ii) or 4b + b = 120° ⇒ 5b = 120° ⇒ b = 24° ⇒ a = 4b = 4 x 24 = 96°Since ∠AOD = ∠COB …. (Vertically opposite angles) ⇒ 2c = 60° + b ⇒ 2c = 60° + 24° = 84° ... c = 42°Hence a = 96°, b = 24°, c = 42°