Question

Two straight lines AB and CD intersect each other at a point O and angle AOC=50°; find:
i) angle BOD
ii) angle AOD
iii) angle BOC

plz tell fast​

Answer 1

Answer:

1) BOD =50°

2) AOD = 130°

3) BOC = 130°

Step-by-step explanation:

BOD= 50° (Vertically opposite angle of AOC)

AOD = 130° ( linear pair of AOC)

BOC = 130 ° ( vertically opposite angle of AOD)

Answer 2

Answer:

1) angle BOD+ angle AOC=180°

=BOD+ 50°=180°

= BOD=50°-180°

BOD=130°

2)AOD+BOD=180°

AOD+130°=180°

AOD=180°-130°

AOD=50°

3)AOD+BOC=180°

130°+ BOC=180°

BOC= 180°130°

BOC=50°