Question

Two straight lines have equations
y=px+4 and py=qx−7, where p and q are constants.
The two lines meet at the point (3,1).
What is the value of q?

Answer 1

Answer:

5

Step-by-step explanation:

It just is 5 no kidding

Answer 2

SOLUTION

GIVEN

• Two straight lines have equations y=px+4 and py=qx−7, where p and q are constants.

• The two lines meet at the point (3,1)

TO DETERMINE

The value of q

EVALUATION

Here the given equation of the lines are

$\sf{y = px + 4 \: \: \: - - - - - (1)}$

$\sf{py = qx - 7 \: \: \: - - - - (2)}$

Now the two lines meet at the point (3,1)

Since equation (1) passes through the point (3,1)

$\sf{1 = 3p + 4}$

$\sf{ \implies \: 3p = - 3}$

$\sf{ \implies \: p = - 1}$

Again Equation (2) passes through the point (3,1)

$\sf{(p \times 1) = (q \times 3) - 7}$

$\sf{ \implies \: p= 3q - 7}$

$\sf{ \implies \: - 1= 3q - 7}$

$\sf{ \implies \: 3q = - 1 + 7}$

$\sf{ \implies \: 3q = 6}$

$\sf{ \implies \: q = 2}$

FINAL ANSWER

Hence the required value of q = 2

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