Question

Two straight lines l1l1 and l2l2 cross each other at point p. The line l1l1 is moving at a speed v1 perpendicular to itself and line l2l2 is moving at a speed v2 in the similar fashion. The speed of point p is :

Answer 1

Speed of the point P = √(v1² + v2²)

Explanation:

Given: Two straight lines l1l1 and l2l2 cross each other at point P. The line l1l1 is moving at a speed v1 perpendicular to itself and line l2l2 is moving at a speed v2 in a similar fashion.

Find: The speed of point P.

Solution:

Let's assume that line l1l1 is oriented horizontally, then its velocity v1 will be in the vertical direction as it should be perpendicular to itself.

Similarly, if line l2l2 is oriented vertically, then its velocity v2 should be perpendicular to itself, hence in the horizontal direction.

At P, the two lines cross each other, so they will have both horizontal and vertical components of velocity.

Net velocity of P can be determined using the formula:

V = √(v1² + v2²)

Answer 2

Answer:

Answer is

$\sqrt{v1 { }^{2} } + v2 { }^{2} + 2v1v2 \cos \alpha \div \sin( \alpha )$

the root is for the whole numerator guys!