Two straight paths are represented by the equations x-3y =2 & -2x + 6y =5 ,check whether the paths cross each other or not.
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Answered by
0
no they will not intersect at any point...
you can check it by using determinant method
you can check it by using determinant method
Answered by
15
Hi ,
x - 3y -2 = 0 ---( 1 )
-2x + 6y - 5 = 0 ---( 2 )
Compare above equations with
a1 x + b1y + c1 = 0 and
a2 x + b2 y + c2 = 0 ,
a1 = 1 , b1 = -3 , c1 = -2 ,
a2 = -2 , b2 = 6 , c2 = -5 ,
a1/a2 = 1/( -2 ) = -1/2 ---( 3 )
b1/b2 = -3/6 = -1/2 -----( 4 )
c1/c2 = -2/(-5 ) = -2/5 ---( 5 )
Therefore ,
a1/a2 = b1/b2 ≠ c1/c2
above equations are parallel to each other.
I hope this helps you.
: )
x - 3y -2 = 0 ---( 1 )
-2x + 6y - 5 = 0 ---( 2 )
Compare above equations with
a1 x + b1y + c1 = 0 and
a2 x + b2 y + c2 = 0 ,
a1 = 1 , b1 = -3 , c1 = -2 ,
a2 = -2 , b2 = 6 , c2 = -5 ,
a1/a2 = 1/( -2 ) = -1/2 ---( 3 )
b1/b2 = -3/6 = -1/2 -----( 4 )
c1/c2 = -2/(-5 ) = -2/5 ---( 5 )
Therefore ,
a1/a2 = b1/b2 ≠ c1/c2
above equations are parallel to each other.
I hope this helps you.
: )
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