Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 107 Pa? Assume that each rivet is to carry one quarter of the load.
Answers
Answer:
Diameter of the metal strip, d = 6.0 mm = 6.0 × 10–3 m
Radius, r = d/2 = 3 × 10-3 m
Maximum shearing stress = 6.9 × 107 Pa
Maximum stress = Manimum load or force / Area
Maximum force = Maximum stress × Area
= 6.9 × 107 × π × (r) 2
= 6.9 × 107 × π × (3 ×10–3)2
= 1949.94 N
Each rivet carries one quarter of the load.
∴ Maximum tension on each rivet = 4 × 1949.94 = 7799.76 N.
Answer:
Explanation:
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Answer:
Diameter of the metal strip, d = 6.0 mm = 6.0 × 10–3 m
Radius, r = d/2 = 3 × 10-3 m
Maximum shearing stress = 6.9 × 107 Pa
Maximum stress = Manimum load or force / Area
Maximum force = Maximum stress × Area
= 6.9 × 107 × π × (r) 2
= 6.9 × 107 × π × (3 ×10–3)2
= 1949.94 N
Each rivet carries one quarter of the load.
∴ Maximum tension on each rivet = 4 × 1949.94 = 7799.76 N.