Question

Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 107 Pa? Assume that each rivet is to carry one quarter of the load.

Answer 1

Here,
Diametre of each rivet (D) = 6mm
radius ( r) =3mm = 3 × 10^-3m
maximum shearing stress on each rivet = 6.9 × 10^7 Pa

Let T be the maximum Tension that can be subjected to the riveted strip .
as each rivet carry one - quarter of the tension .
So, Tension on each rivet = T/4

Maximum shearing stress = maximum shearing force/Area
6.9 × 10^7 = (T/4)/πr²
T = 6.9 × 10^7 ×4πr²
=6.9 ×10^7 ×4×3.14×(3×10^-3)²
= 6.9×4×3.14 × 9 × 10^(7-6)
= 7.8 × 10³ N

Answer 2

Answer:

7.8×10^3 N

Explanation:

FOR ONE RIVET = 1949.94 N

FOR FOUR RIVETS = 1949.94 × 4

= 7799.76

= 7.8×10^3 N