Two student a and b calculate the charge flowing through a circuit a concludes that 300 Celsius of charge flows in 3 minutes B conclude that 3.125* 10 to the power 19 electrons flow in one second if the current measured in the circuit is 5A then the correct calculation is
Answers
Answer:
For first student,
Use following formula to find electric current,
Substitute, 300 C for Q and 3 min for t,
Current flow in circuit is 300÷180s
=5/3 A
Answer:
The correct calculation is that 900 Coulombs of charge flows through the circuit.
Explanation:
The correct calculation is to use the formula:
Q = I*t
where Q is the charge flowing through the circuit, I is the current, and t is the time.
For student A, Q = 300 C and t = 3 min = 180 s. Therefore:
Q = 300 C / 180 s = 1.67 C/s
For student B, the number of electrons flowing per second is given as 3.125 × 10^19 electrons/s. We know that one electron has a charge of 1.602 × 10^-19 C, so the total charge flowing per second is:
Q = (3.125 × 10^19 electrons/s) × (1.602 × 10^-19 C/electron) = 0.5 C/s
We can see that the two calculations are not the same, so we need to determine which one is correct. Since the current measured in the circuit is given as 5A, we can use this information to check the calculations.
Using the formula for current:
I = Q/t
we can rearrange to solve for Q:
Q = I*t
If we substitute the given values of I and t, we get:
Q = (5A) × (1 s) = 5 C
So we can see that the correct calculation is the one that gives a value closest to 5 C.
Using student A's calculation:
Q = 1.67 C/s × (60 s/min) × 3 min = 300 C
This gives a value of 300 C, which is too high.
Using student B's calculation:
Q = 0.5 C/s × (1 s) = 0.5 C
This gives a value of 0.5 C, which is too low.
Therefore, neither calculation is correct, and we need to recalculate using the correct formula:
Q = I*t = 5A × 180 s = 900 C
So the correct calculation is that 900 Coulombs of charge flows through the circuit.
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