Two student appeared at an exam. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them ?
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Let their marks be (x+9) and x.
Then, x+9 = 56/100(x + 9 +x)
=> 25(x+9)
=> 14 (2x + 9)
=> 3x = 99
=> x = 33.
So, their marks are 42 and 33
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