Question

Two student appeared at an examination one of them secured 9 marks more than the other and his marks was 56% of the sum of their marks the marks obtained by them are

Answer 1

Given:

One student score 9 marks more than the other student.

The same student gets marks 56% of the sum of their marks.

Calculation:

Let the marks of one student be x.

Let the marks of other student be (x + 9).

The sum of their marks = x + x + 9 = 2x + 9

According to the question;

⇒ (x + 9) = 14/25 × (2x + 9)

⇒ 25x + 225 = 28x + 126

⇒ 3x = 99

⇒ x = 33

The marks of the one student = 33

⇒ (x + 9) = 56/100 × (2x + 9)

Answer 2

Answer:

75

Step-by-step explanation:

let first student marks be A

2nd (a+9)

the sum of their marks =a+a+9 =2a+9

now we will subtract the 2nd students marks from the whole

(a+9)=56/100(2a+9)

100(a+9)= 56(2a+9)

100a+900=112a+504

12a=396

a=33

a+9 = 42