Math, asked by deepakbargoti18, 11 months ago


Two students. A and B. appeared for an examination. A secured 8 marks more than B and the marks of the former was
55% of the sum of their marks. The sum of the marks obtained by A and B is:

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Answers

Answered by Anonymous
7

Answer:

Option(B)

Step-by-step explanation:

Let marks of the 1st guy = x

Then marks of 2nd guy = x + 8

Sum of their marks = x + (x + 8) = 2x + 8   ----- (1)

According To the Question -

(x + 8) = 55% of 2x + 8

=>  (x + 8) = 55/100 * 2x + 8

=> -x = -36

=> x = 36

Place x in (1), we will get

=> 2(36) + 8

=> 72 + 8

=> 80

Hence, Sum of marks = 80

#MarkAsBrainliest

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