Math, asked by PriyaRanawat511, 27 days ago

Two students appeared at an examination. One of tham se-
cured 9 marks more than the other and his marks was 56% of
the sum of their marks. The marks obtained by them are
(A) 42,33
(B)43,34
(C)41,32
(D) 39,30​

Answers

Answered by Anonymous
3

Answer:

option c

Step-by-step explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56/100 (x + 9 + x)  

25(x + 9) = 14(2x + 9)

3x = 99

 x = 33

So, their marks are 42 and 33.

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