Math, asked by vivek1000053, 4 months ago

Two students appeared at an examination. One of them secured 18marks more than the other and his

marks was 72% of the sum of their marks. What are the marks obtained by them?​

Answers

Answered by krushindraborale706
3

Answer:

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Answered by kumargudla11
0

Answer:

Let the marks secured by them be x and (x + 18)

Then sum of their marks = x + (x + 18) = 2x + 18

Given that (x + 18) was 72% of the sum of their marks

=>(x+18) = 72/100(2x+18)

=>(x+18) = 18/25(2x+18)

=> 25x + 450 = 36x + 324

=> 11x = 126  x = 11.45

Then (x + 18) = 11.45 + 18 = 29.45

Hence their marks are 11.45 and 29.45

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