Two students appeared at an examination. One of them secured 18marks more than the other and his
marks was 72% of the sum of their marks. What are the marks obtained by them?
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Let the marks secured by them be x and (x + 18)
Then sum of their marks = x + (x + 18) = 2x + 18
Given that (x + 18) was 72% of the sum of their marks
=>(x+18) = 72/100(2x+18)
=>(x+18) = 18/25(2x+18)
=> 25x + 450 = 36x + 324
=> 11x = 126 x = 11.45
Then (x + 18) = 11.45 + 18 = 29.45
Hence their marks are 11.45 and 29.45
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