Two students appeared at an examination. one of them secured 10 marks more than the other and his marks was 60%of the sum of their marks. The marks obtained by the better student are:
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Let marks obtained by the one student be x
Therefore, marks obtained by other student = x + 10
Sum of their marks = x + x + 10 = 2x + 10
Therefore, 60% of 2x + 10 = x + 10
= 60/100 * 2x + 10 = x + 10
= 3/5 * 2x + 10 = x + 10
= 6x + 30/5 = x + 10
= 6x + 30 = 5x + 50
= 6x - 5x = 50 - 30
= x = 20.
Marks obtained by the better student = x + 10 = 20 + 10 = 30 (Ans)
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