Math, asked by honey072, 1 year ago


two students appeared at an examination. One of them secured 9 marks more than the other and his manke
60% of the sum of their marks. The marks obtained by them are :
(b) 41, 32
(c) 42,33
(d) 43, 34
(a) 39, 30

Answers

Answered by annoyingjustin
5

(c) Is the correct answer

Both's Marks Difference= 9

Difference in percentage= 12%

1st student marks = 56% = 56/12 ×9 = 42

2nd student marks = 44% = 44/12 ×9 = 33

pls mark as brainliest

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