Two students appeared for an examination. One of them secured 9 marks more than the other and score was 56% of the sum of their marks. The marks obtained by them are:
Answers
Answered by
5
Step-by-step explanation:
Let their marks be (x + 9) and x.
Then, x + 9 = 56 / 100 (x + 9 + x)
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Answered by
1
Answer:
33
Step-by-step explanation:
Let the marks of the 1st guy = x
Let the marks of 2nd guy = x + 9
Sum of their marks = x + (x+9) = 2x+9
According To the Question -
(x+9) = 56% of 2x+9
=> (x+9) = 56/100 * 2x+9
=> 25(x+9) = 14(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
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