Question

Two students appeared for an examination. One of them secured 21 marks more than the other and his marks were 80% of the sum of their marks. The marks obtained by them are

A) 88 and 67 B) 89 and 68 C) 28 and 7 D) 98 and 77

Answer 1

Answer:

let the marks of A be x + 21. let the marks of B be x.

x+24 = 80% of x+x+24

x+ 24= 80% of 2x +24

x+24= 1.6x +19.2

-0.6x = - 4.8

x= 8

x+21=29

Marks scored by A is 29 and B is 8

Hope this helps you please mark my answer as brainliest dude