Two students appeared for an examination. One of them secured 9 marks more than the other and his score was 56% of the sum of their marks. The marks obtained by them are:
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This student scored 42 while other student scored 33
Step-by-step explanation:
Let the marks scored by student A be x
Then the marks scored by this student B will be x+9
Sum of the marks scored by both the students; x + (x+9) = 2x+9
The marks scored by B are given as 56% of 2x+9 =56(2x+9)/100
= 28x+(14x9)/25
= 28x+(14x9)/25 =(x+9 )
= 28x+(14x9) = 25(x+9 )
= 28x - 25x = 9(25-14)
= 3x = 9x11 = 99
= x = 99/3 = 33 (Marks obtained by A
= x+9 = 33 +9 = 42 (Marks obtained by B)
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