Math, asked by KANHAIYAJEE, 1 year ago

two students appeared for an examination one of them secured 24 marks more than the other and his marks was 65% of the sum of their marks the marks obtained by them are​

Answers

Answered by dzboss81
3

Answer:

Let the marks of the 1st guy = x

Let the marks of 2nd guy = x + 9

Sum of their marks = x + (x+9) = 2x+9

According To the Question -

(x+9) = 56% of 2x+9

=>  (x+9) = 56/100 * 2x+9

=>  25(x+9) = 14(2x+9)

=>  25x + 225 = 28x + 126

=>  3x = 99

=>  x = 33

Step-by-step explanation:

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