Two students appeared in an examination one of them secured nine marks more than the other and his marks were 56% of the sum of their marks find the marks obtained by them. The answer at the back is 36 and 45
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Let the marks of the 1st guy = x
Let the marks of 2nd guy = x + 9
Sum of their marks = x + (x+9) = 2x+9
According To the Question -
(x+9) = 56% of 2x+9
=> (x+9) = 56/100 * 2x+9
=> 25(x+9) = 14(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 3
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