Question

two students appeared in an examination one of them secured 9 marks more than the other and his marks was 56% of the sum of their marks find the marks obtained by them

Answer 1

Heya, here is your Answer :-

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Let marks secured by Student A be x and by Student B be y.

According to the Question :-
x = 9 + y ———————————— eq. 1

and,

x = 56% of (x + y)
x = 56x/100 + 56y/100
100x = 56x + 56y
100x - 56x = 56y
44x = 56y
x = 56y/44

Substituting value of x to eq. 1

x = 9 + y
56y/44 = 9 + y
56y/44 - y = 9
56y - 44y/44 = 9
12y/44 = 9
y = 9*44/12
y = 33 Marks

So,
x = y+9 = 33+9 = 42 Marks

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So,
Final Answer :-
Marks of Student A = x = 42 Marks
Marks of Student B = y = 33 Marks

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