Question

Two students are selected at random from a group of 10 boys and 12 girls

1)Find the probability that they are both girls

2)Find the probability one is a boy and the other is a girl

I will give 5 stars if it is correct

Answer 1

Answer:

1)total outcomes=12

no of possible =2

probability=2/12

=1/6

2)total outcomes=22

no of possible=2

probability=2/22

=1/11

please mark it as brainliest answer

Answer 2

a) $\dfrac{2}{7}$  b) $\dfrac{40}{77}$

Step-by-step explanation:

Since we have given that

Number of boys = 10

Number of girls = 12

So, 1)Find the probability that they are both girls

$\dfrac{^{12}{C_2}{^{22}C_2}=\dfrac{66}{231}=\dfrac{22}{77}=\dfrac{2}{7}$

2)Find the probability one is a boy and the other is a girl

$\dfrac{10\times 12}{^{22}C_2}=\dfrac{120}{231}=\dfrac{40}{77}$

Hence, a) $\dfrac{2}{7}$  b) $\dfrac{40}{77}$