Two students are solving the same problem independently. if the probability that the first one solves the problem is 3/5 and the probability that the second solves the problem is4/5 what is the probability that atleast one of them solves the problem
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Probability of first = 3/5
Probability of second = 4/5
Since A and B are independent.
P(A.B) = 3/5*4/5 = 12/25
P(Exactly one of them solves) = P(A) + P(B) - 2P(A.B)
= 3/5 + 4/5 - 2*12/25
= 7/5 - 24/25
=35-24/25
=11/25
P(it cannot be solved) = (1-3/5)(1-4/5)
=(2/5)(1/5)
= 2/25
P(it can be solved) = (1-2/25)
=23/25
Please mark as Branliest!
Probability of second = 4/5
Since A and B are independent.
P(A.B) = 3/5*4/5 = 12/25
P(Exactly one of them solves) = P(A) + P(B) - 2P(A.B)
= 3/5 + 4/5 - 2*12/25
= 7/5 - 24/25
=35-24/25
=11/25
P(it cannot be solved) = (1-3/5)(1-4/5)
=(2/5)(1/5)
= 2/25
P(it can be solved) = (1-2/25)
=23/25
Please mark as Branliest!
bhumi1423:
ans is 23/25
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