Two students took an exam, one scored 9 marks more than the other, and he scored 56% of total marks then what are the marks of the students?
Answers
Answered by
1
x+9 = 56/100(x +9+x)
56/100 =14/25
25(x+9) =14(2x+9)
3x =99
x=33
marks are 42 and 33
56/100 =14/25
25(x+9) =14(2x+9)
3x =99
x=33
marks are 42 and 33
Jenita:
then whose wish
thats the wish of brainly
ok
ya
bye
were we chatting ?
going ofline
no
COOL...!
why ur not replaying
Answered by
0
A nd B are students. B scored marks x. A scored x+9.
total = 2x + 9
A scored : x + 9 = 56/100 * (2x+9) = 14 /25 * (2 x + 9 )
=> 25 (x + 9) = 14 (2x+9)
=> 25 x + 225 = 28 x + 126
=> 99 = 33 x
=> x = 33
So A scored 42 and B scored 33 marks.
total = 2x + 9
A scored : x + 9 = 56/100 * (2x+9) = 14 /25 * (2 x + 9 )
=> 25 (x + 9) = 14 (2x+9)
=> 25 x + 225 = 28 x + 126
=> 99 = 33 x
=> x = 33
So A scored 42 and B scored 33 marks.
Similar questions