Question

two substance A and B have specific heats c and 2 c respectively. if A and B are given Q and 4Q amounts of heat respectively, the change in their temperatures in the same . if the mass of A is m, what is the mass of B.


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Answer 1

Answer:

The mass of B such that B has quantity of heat 4Q, heat capacity 2c and same temperature change as A is 2m.

Explanation:

Step 1 : Write down the formula for getting the quantity of heat.

Let the quantity of heat be Q, the specific heat capacity be c and the temperature change be T and the mass of the substance be m.

Q = mcT

Now asking T the subject of the equation we have :

T = mc/Q

Step 2 : Identify the values given and substitute in the formula.

A :

Mass = m

Specific heat capacity = c

Quantity of heat = Q

Let the change in temperature for both be T.

B :

Quantity of heat = 4Q

Specific heat capacity = 2c

Mass =?

Temperature = T.

From the formula :

M = 4Q/2cT........... 1)

From A we can get T.

T = Q/mc

Substitute this equation 1.

M = 4Q/(2c × Q/mc)

= 4Q ÷ 2Q/m

= 4Q × m/2Q = 2m

Therefore the mass of B will have a mass of 2m.