Two substance P4 & 02 are allowed to react completely to form mixture of P4O6 and leaving none of the reactants. Using this information calculate the moles of P406, and P4010.. in the final
mixture when the following amounts of P4 & O2 are taken.
P4 +302
P4 + 502
(i) If I mole P4 & 4 mole of O2
(ii) If 3 mole P4 & 11 mole of O2
(ii) If 3 mole P4. & 13 mole of O2
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Answer:
(i)P
4
+3O
2
→P
4
O
6
0.5 1.5 0.5
P
4
+5O
2
→P
4
O
10
0.5 2.5 0.5
(ii) P
4
+3O
2
→P
4
O
6
2 6 2
P
4
+5O
2
→P
4
O
10
1 5 1
(iii) P
4
+3O
2
→P
4
O
6
1 3 1
P
4
+5O
2
→P
4
O
10
2 10 2
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