Question

two successive price increase of 10% and 20% of an article are equivalent to a single price increase of percentage?

Answer 1

hi Ram ,

100.......10%↑ = 110......20%↑ = 132

calculations
10% of 100 = (10/100)*100 = 10
20% of 110 = (20/100)*110 = 22

so total price increase = 32%.

Hope it helped.
Let me know if any doubts.
Cheers !!!

Answer 2

The price of article increased by 32%.

Step-by-step explanation:

Let the initial price of the article is x.

Two successive price increase of 10% and 20%.

Price of article after increase of 10% is

$x+\frac{10}{100}x=x+0.1x=1.1x$

Price of article after second increase of 20% is

$1.1x+\frac{20}{100}(1.1x)=1.1x+0.22x=1.32x$

New price of article after two successive price increase of 10% and 20% is 1.32x.

Total increase in price is

$Increase=\dfrac{\text{New price - Initial price}}{\text{Initial price}}\times 100$

$Increase=\dfrac{1.32x-x}{x}\times 100$

$Increase=\dfrac{0.32x}{x}\times 100$

$Increase=0.32\times 100$

$Increase=32$

Therefore, the price of article increased by 32%.

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