TWO SUPPLEMENTARY ANGLE ARE SUCH THAT TWO TIMES THE MEASURES OF ONE IS EQUAL TO THREE TIMES THE MEASURES OF THE OTHER.FIND THE MEASURES OF THE ANGLES.
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Answered by
0
let the one angle be x and other be y
then 2x= 3y......... x= 3/2y
also x+y= 180
put x= 3/2y in equation
3/2y+ y= 180
5/2y= 180
y= 72 degrees
and x= 3/2y= 3/2(72)= 108 degrees...
then 2x= 3y......... x= 3/2y
also x+y= 180
put x= 3/2y in equation
3/2y+ y= 180
5/2y= 180
y= 72 degrees
and x= 3/2y= 3/2(72)= 108 degrees...
Answered by
3
Let the two supplementary angles are x and 180° - x
According to question :-
=> 2x = 3(180° - x)
=> 2x = 540° - 3x
=> 2x + 3x = 540°
=> 5x = 540°
=> x = 540°/5
=> x = 108°
So, the two angles are 108° and 72°
Hope this helps.....
According to question :-
=> 2x = 3(180° - x)
=> 2x = 540° - 3x
=> 2x + 3x = 540°
=> 5x = 540°
=> x = 540°/5
=> x = 108°
So, the two angles are 108° and 72°
Hope this helps.....
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