Question

Two supplementary angle diffe by 56.
Find the angles. ​

Answer 1

Answer:

Let one angle be x.

Let the other angle be (180° - x)

x + 180° - x = 56°

2x = 360°

x = 118°

One angle x = 118°

The second angle (180° - x) = 180° - 118° = 62°

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Answer 2

Answer:

Given :-

• Two supplementary angles differ by 56°.

To Find :-

• What are the angles.

Solution :-

Let,

$\mapsto \bf First\: Angle =\: x$

$\mapsto \bf Other\: Angle =\: 180^{\circ} - x$

According to the question :

$\bigstar$ Two supplementary angles are differ by 56°.

So,

$\small \implies \bf \bigg\{First\: Angle\bigg\} - \bigg\{Other\: Angle\bigg\} =\: 56^{\circ}$

$\implies \sf x - (180^{\circ} - x) =\: 56^{\circ}$

$\implies \sf x - 180^{\circ} + x =\: 56^{\circ}$

$\implies \sf x + x =\: 56^{\circ} + 180^{\circ}$

$\implies \sf 2x =\: 236^{\circ}$

$\implies \sf x =\: \dfrac{236^{\circ}}{2}$

$\implies \sf\bold{\purple{x =\: 118^{\circ}}}$

Hence, the required angles are :

❒ First Angle :

$\dashrightarrow \sf First\: Angle =\: x$

$\dashrightarrow \sf\bold{\red{First\: Angle =\: 118^{\circ}}}$

❒ Other Angle :

$\dashrightarrow \sf Other\: Angle =\: (180^{\circ} - x)$

$\dashrightarrow \sf Other\: Angle =\: (180^{\circ} - 118^{\circ})$

$\dashrightarrow \sf\bold{\red{Other\: Angle =\: 62^{\circ}}}$

$\sf\boxed{\bold{\purple{\therefore\: The\: angles\: are\: 118^{\circ}\: and\: 62^{\circ}\: .}}}$