Question

two supplementary angles are (4p+12) and (6p +8) find p. also find the angles
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Answer 1

hope this will help you

thank you

Answer 2

(4p+12)+(6p+8)=180

4p+12+6p+8=180

10p+20=180

10p=160

p=16

∠ 4p+12=4(16)+12

          =64+12

          =∠76

∠ 6p+8=6(16)+8

         =96+8

         =∠104