Question

two supplementary angles are differ by 48degree.find the angles

Answer 1

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1st angle=x
2nd angle=180-x

ATQ

$2x + 48 = 180 \\ 2x = 180 - 48 \\ x = \frac{132}{2} \\ x = 66$
1st angle=66°
2nd angle=180°-66°=114°
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