two supplementary angles are in the ratio 11:7. find the angles.
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Answered by
4
Hey!
Let one angle be 11x°.
Let the other angle be 7x°.
According to your problem, they are supplementary angles.
Hence,
11x+7x=180
=>18x=180
=>x=10
The first angle = (10×11) = 110°.
The second angle = (10×7) = 70°.
Hope this helps you!
Let one angle be 11x°.
Let the other angle be 7x°.
According to your problem, they are supplementary angles.
Hence,
11x+7x=180
=>18x=180
=>x=10
The first angle = (10×11) = 110°.
The second angle = (10×7) = 70°.
Hope this helps you!
rohit9548:
hello
Answered by
28
Two supplementary angles are in the ratio of 11 : 7.
Find the angles.
Let the first angle be 11x°
And the other angle 7x°
Hence,
7x + 11x = 180
18x = 180
x = ?
x = 180 ÷ 18
x = 10
Now,
7 × 10 = 70
11 × 10 = 110
Therefore,
The angles are and
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