Question

two supplementary angles are in the ratio 2.3 find the angle​

Answer 1

Answer:

72° , 108°

Step-by-step explanation:

ratio of angles=2:3

let common ratio be x.

so, according to question

2x+3x=180°

=>5x=180°

x=36°

so, angles are

2x=2*36=72°

3x=3*36=108°

HOPE IT HELPS,

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Answer 2

$\huge\sf\underline{\underline{\pink{ Answer:-}}}$

first angle => 72°

second angle => 108°

$\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}$

There are two supplementary angles have the ratio 2:3 find the angles?

$\sf\underline{\underline{\green{GIVEN \: }}}$

Ratio between two supplementary angle

$= > 2 : 3$

$\sf\underline{\underline{\green{TO \: FIND \: }}}$

find the angles?

$\huge\underline\mathbb{\red S\pink {0} \purple {L} \blue {UT} \orange {1}\green {ON :}}$

Let the angle be 2x and 3x

$\sf\underline{\underline{\pink{We \: know, \: }}}$

The measure of two angles of supplementary angles is 180°.

$\sf\underline{\underline{\green{ACCORDING \: TO \: THE \: QUESTION, \: }}}$

$= > 2x + 3x = 180°$

$= > 5x = 180°$

$= > x = \frac{180 {}^{o} }{5}$

$= >x = 36 {}^{o}$

$\sf\underline{\underline{\green{HENCE, \: }}}$

$\sf\underline{\underline{\red{First \: Angle \: }}}$

$= > 2x$

$= > 2 \times 36 {}^{o}$

$= > {72}^{o}$

$\sf\underline{\underline{\red{Second \: Angle \: }}}$

$= > 3x$

$= > 3 \: \times 36{}^{o}$

$= > 108 {}^{o}$