Question

two supplementary angles are in the ratio 4.5 find the angle​

Answer 1

Answer:

ratio = 4:5

4x + 5x = 180

9x = 180

x= 180/9

x = 20

4x = 80

5x =100

Answer 2

$\huge\sf\underline{\underline{\pink{ Answer:-}}}$

first angle => 80°

second angle => 100°

$\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}$

There are two supplementary angles have the ratio 4:5 find the angles?

$\sf\underline{\underline{\green{GIVEN \: }}}$

Ratio between two supplementary angle

$= > 4:5$

$\sf\underline{\underline{\green{TO \: FIND \: }}}$

find the angles?

$\huge\underline\mathbb{\red S\pink {0} \purple {L} \blue {UT} \orange {1}\green {ON :}}$

Let the angle be 4x and 5x

$\sf\underline{\underline{\pink{We \: know, \: }}}$

The measure of two angles of supplementary angles is 180°.

$\sf\underline{\underline{\green{ACCORDING \: TO \: THE \: QUESTION, \: }}}$

$= > 4x + 5x = 180°$

$= > 9x = 180°$

$= > x = \frac{180 {}^{o} }{9}$

$= >x = 20 {}^{o}$

$\sf\underline{\underline{\red{HENCE, \: }}}$

$\sf\underline{\underline{\pink{First \: Angle \: }}}$

$= > 4x$

$= > 4 \times 20 {}^{o}$

$= > 80 {}^{o}$

$\sf\underline{\underline{\pink{Second \: Angle \: }}}$

$= > 5x$

$= > 5 \: \times 20{}^{o}$

$= > 100 {}^{o}$