Question

Two supplementary angles are such that the measure of one angle is 4/5 of the measure of the other anglw .Find the measure of the angles
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Answer 1

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Given:

There are two supplementary angles.

Measure of one angle is 4/5 times of another one.

To Find:

What is the measure of both angles ?

Solution:

Let the two angles be x and y. Where

⇒ x = 4/5 times of y

⇒ x = 4/5 × y

⇒ x = 4y/5ㅤㅤㅤㅤㅤeq.1

As we know that ,

Sum of Supplementary angles = 180°

⇒ x + y = 180°

⇒ 4y/5 + y = 180°

so

⇒ 4y + 5y/5 = 180°

⇒ 9y = 180° × 5

⇒ 9y = 900°

⇒ y = 900°/9

⇒ y = 100°

So the measure of one angle is 100° and of other is -

⇒ x = 4/5 × 100

⇒ x = 4 × 20

⇒ x = 80°

Hence

Two angles are 100° and 80°.

Answer 2

Answer:

hi how u made tat trigonometry table in my ques what is the formula..??

the above ans is crct

thanks for giving formula see i done..i followed ur 1st id..

$\begin{gathered}\sf \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c| c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^ { \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac { \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}$