Question

two supplementary angles are X + 42 degree and 3 x minus 62 degree find x

Answer 1

(x+42) + (3x-62) = 180
=x+42+3x-62=180
=4x-20=180
=4x=160
=x=160/4
=x= 40
so,the value of x=40°

plz mark as brainliest

Answer 2

(x+42)+(3x-62)=180 x+42+3x-62=180 4x-20=180 4x=200 x=50