Question

Two supplementary angles differ by 20 degree. Find the measure of each angle.

Answer 1

Answer:

The angles are 80° and 100°.

Step-by-step explanation:

Let the one angle be x°, so other will be (180 - x)°.

A/q

→ (x°) - [(180 - x)°] = 20

→ x° - 180 + x° = 20

→ 2x° = 200

→ x° = 200/2

→ x° = 100°

The angles are :

→ x° = 100°

→ (180 - x)° = (180 - 100)° = 80°

Answer 2

One supplementary angle be x and second x-20

A/q

We know sum of any.of supp.be 180°

supplementary angles differ=180°

by 20

$x + (x- 20) = 180$

$2x - 20 = 180$

$2x = 180 + 20$

$x = \frac{200}{2}$

$x = 100$

$x - 20 = > 100 - 20 = 80$