two supplementary angles differ by 39 degree. find the angles
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Answered by
6
Heya !!!
Here is Your Answer.
Given that two supplementary angles differ by 39°.
Let one angle be x and other be y.
x+y = 180° (as they are supplementary). (i)
x-y = 39° (ii)
Adding eq. (I) and (ii), we get....
x + y = 180
x - y = 39
------------------
2x = 219
x = 109.5°
y = 180 - 109.5 = 70.5°
Hence, the two angles are 109.5° and 70.5°
Hope.It Helps
Here is Your Answer.
Given that two supplementary angles differ by 39°.
Let one angle be x and other be y.
x+y = 180° (as they are supplementary). (i)
x-y = 39° (ii)
Adding eq. (I) and (ii), we get....
x + y = 180
x - y = 39
------------------
2x = 219
x = 109.5°
y = 180 - 109.5 = 70.5°
Hence, the two angles are 109.5° and 70.5°
Hope.It Helps
RehanAhmadXLX:
:-)
Answered by
4
Heya !!!
Let First angle be X°
Other angles be Y°.
Therefore,
X - Y = 39°--------(1)
And,
X+ Y = 180° ----(2)
From EQUATION (1) we get,
X - Y = 39
X = 39 +Y ------(3)
Putting the value of X in equation (2)
X + Y = 180°
39 + Y + Y = 180°
2Y = 180°-39
2Y = 141
Y = 141/2
Y = 70.5°
Putting the value of Y in equation (3)
X = 39 + Y
X = 39 + 79.5 = 109.5°
Hence,
Two supplementary angles are 70.5 and 109.5°.
HOPE IT WILL HELP YOU..... :-)
Let First angle be X°
Other angles be Y°.
Therefore,
X - Y = 39°--------(1)
And,
X+ Y = 180° ----(2)
From EQUATION (1) we get,
X - Y = 39
X = 39 +Y ------(3)
Putting the value of X in equation (2)
X + Y = 180°
39 + Y + Y = 180°
2Y = 180°-39
2Y = 141
Y = 141/2
Y = 70.5°
Putting the value of Y in equation (3)
X = 39 + Y
X = 39 + 79.5 = 109.5°
Hence,
Two supplementary angles are 70.5 and 109.5°.
HOPE IT WILL HELP YOU..... :-)
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