Question

Two supplementary angles differ by 42 degree one of these angle is. plz five whole solution​

Answer 1

∴Let the smaller angle be x°

∴Since the two angles differ by 42° the bigger angle =x+34°

∴Since the sum of the supplementary angles is 180°

=>We have x+(x+42)=180°

=>2x+42=180°

=>2x=180−42

=>2x=138

=>x=$\frac{138}{2}=69$°

∴Therefore smaller angle =x=69°

∴Bigger angle =x+42=69+42=153°

Answer 2

Given,

The difference between the two supplementary angles is 42.

To find,

One of the angles.

Solution,

The solution to this problem could be found simply by using the below process.

Let one of the angles be x.

According to the given condition, the second angle should be (x-42), since the two angles differ by 42.

Firstly we should know what the supplementary angles are. So two angles are said to be supplementary angles if the sum of these two angles is 180°.

Say, if a and b are supplementary angles then they must follow the following condition

$a+b=180\textdegree$

Now, for this question,

$x+(x-42)=180\textdegree$

Simplifying the above equation,

$2x-42=180\textdegree$

$2x=180+42$

$2x=222$

$x=111\textdegree$

That is, the value of one of the angles is 111°.

Since the second angle should be equal to (x-42). We can find the second angle by substituting the obtained value of x in this expression.

Hence, the second angle will be

$x-42\\=111-42\\=69\textdegree$

Therefore the values of the two supplementary angles will be 111° and 69°.