Two supplementary angles differ by 42°. One of these angles is?
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Answer:
111° and 69°
Step-by-step explanation:
Let the angles be x and (x-42°).
Now, sum of supplementary angles = 180°
∴ x + (x-42°) = 180°
2x = 180 + 42
2x = 222
∴ x = 111°
The angles are 111° and (111-42) = 69°
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