Math, asked by mamatadhal1979, 19 days ago

Two supplementary angles differ by 42°. One of these angles is?​

Answers

Answered by Mathsisthebest
2

Answer:

111° and 69°

Step-by-step explanation:

Let the angles be x and (x-42°).

Now, sum of supplementary angles = 180°

∴ x + (x-42°) = 180°

2x = 180 + 42

2x = 222

∴ x = 111°

The angles are 111° and (111-42) = 69°

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